3x^2+2x+7=2x+5

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Solution for 3x^2+2x+7=2x+5 equation: 



3x^2+2x+7=2x+5

We move all terms to the left:

3x^2+2x+7-(2x+5)=0

We get rid of parentheses

3x^2+2x-2x-5+7=0

We add all the numbers together, and all the variables

3x^2+2=0

a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation

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